Exercise Answers

Module 1: Order of Operations

  1. 7
  2. 13
  3. 7
  4. 13
  5. 2
  6. 8
  7. 18
  8. 6
  9. 25
  10. 49
  11. 80
  12. 31
  13. 28
  14. 67
  15. 22
  16. 4
  17. 160
  18. 19
  19. 2
  20. 12
  21. 40
  22. 200
  23. 2
  24. 14
  25. 9\cdot2+30=48°F
  26. (72-30)\div2=21°C

Module 2: Negative Numbers

  1. 5
  2. 5
  3. -15
  4. -22
  5. 4
  6. -4
  7. -9
  8. 9
  9. 18°F
  10. 3
  11. -200
  12. 3
  13. -3
  14. -7
  15. -7
  16. 7
  17. 7
  18. 3
  19. -3
  20. 55
  21. 55
  22. 11,123\text{ ft}
  23. 543\text{ ft}
  24. -12
  25. -40
  26. 18
  27. 21
  28. 4
  29. -8
  30. 16
  31. -32
  32. -7
  33. -4
  34. 9
  35. 0
  36. 0
  37. undefined
  38. 19
  39. -73
  40. 1
  41. -6
  42. -8
  43. 40

Module 3: Decimals

If you’ve seen Modules 5 & 6, don’t worry about accuracy or precision on these exercises.

  1. 90.23
  2. 7.056
  3. 16.55
  4. 184.015
  5. 8.28
  6. 15.756
  7. 4,147
  8. 414.7
  9. 41.47
  10. 4.147
  11. 65,625
  12. 65.625
  13. 6.5625
  14. \textdollar656.25
  15. 243.5
  16. 2,435
  17. 243,500
  18. 24.35
  19. 6,000
  20. 6,380
  21. 0.71
  22. 0.715
  23. \textdollar3.67 per month
  24. 7.5 miles per hour

Module 4: Fractions

  1. \frac{11}{30}
  2. \frac{19}{30}
  3. \frac{12}{15}
  4. \frac{8}{12}
  5. 7
  6. 1
  7. 0
  8. undefined
  9. \frac{3}{4}
  10. \frac{5}{3}
  11. 2
  12. \frac{1}{2}
  13. \frac{5}{12}
  14. 1
  15. at least 45 questions
  16. 16
  17. \frac{3}{5}
  18. 6 scoops
  19. A requires \frac{1}{12} cup more than B
  20. \frac{1}{2} of the pizza
  21. \frac{2}{3} more
  22. \frac{5}{8} inches combined
  23. \frac{1}{8} inches difference
  24. \frac{7}{12} combined
  25. \frac{1}{12} more
  26. 2.75
  27. 0.35
  28. 0.\overline5 or 0.555...
  29. 1.\overline{63} or 1.636363...
  30. 11\frac{1}{2}
  31. 4\frac{2}{3}
  32. \frac{11}{5}
  33. \frac{20}{3}
  34. 10\frac{3}{8}
  35. 4\frac{7}{8}
  36. 8\frac{1}{6}
  37. 1\frac{5}{6} cup

Module 5: Accuracy and Significant Figures

  1. exact value
  2. approximation
  3. exact value
  4. approximation
  5. exact value
  6. approximation
  7. three significant figures
  8. four significant figures
  9. five significant figures
  10. two significant figures
  11. three significant figures
  12. four significant figures
  13. two significant figures; the actual value could be anywhere between 28,500 and 29,500
  14. three significant figures; the actual value could be anywhere between 28,950 and 29,050
  15. four significant figures; the actual value could be anywhere between 28,995 and 29,005
  16. five significant figures; the actual value could be anywhere between 28,999.5 and 29,000.5
  17. 51,800
  18. 51,840
  19. 4.3
  20. 4.28
  21. 14,000
  22. 14,\overline{0}00
  23. 2.6
  24. 2.60
  25. 29,000\text{ ft}
  26. 29,\overline{0}00\text{ ft}
  27. 29,030\text{ ft}
  28. 29,032\text{ ft}
  29. 29,031.7\text{ ft}
  30. 107
  31. 640
  32. 14.4
  33. 12
  34. \textdollar23

Module 6: Precision and GPE

  1. thousands
  2. hundreds
  3. tens
  4. thousandths
  5. ten thousandths
  6. hundred thousandths
  7. 82,000
  8. 82,\overline{0}00
  9. 82,0\overline{0}0
  10. 0.6
  11. 0.60
  12. 0.600
  13. 39.3 lb
  14. 39 lb
  15. \textdollar9,800
  16. \textdollar8\overline{0}0
  17. thousands place; the nearest 1,000 people
  18. \pm 500 people
  19. hundred thousandths place; the nearest 0.00001 in
  20. \pm 0.000005 in
  21. hundredths place; the nearest 0.01 mil
  22. \pm 0.005 mil
  23. 30\overline{0} miles
  24. ones place; the nearest 1 mile
  25. \pm 0.5 mi
  26. ones place; the nearest 1 minute
  27. \pm 0.5 min
  28. two sig figs
  29. three sig figs
  30. 55 mi/hr
  31. When dividing, we must round the result based on the accuracy; i.e., the number of significant figures.

Module 7: Formulas

  1. \textdollar2.46
  2. \textdollar4.14
  3. \textdollar17.80
  4. \textdollar24.80
  5. \textdollar3.80
  6. 6 representatives
  7. 10 representatives
  8. 52 representatives
  9. 8 electoral votes
  10. 12 electoral votes
  11. 54 electoral votes
  12. \approx115°F; the official record high in the city was 116°F.
  13. 37°C
  14. -0.4°F
  15. 200°C
  16. 90 mm Hg
  17. around 107 mm Hg
  18. 70 in
  19. 74 in
  20. yes
  21. no; too large
  22. no; too small
  23. yes

Module 8: Perimeter and Circumference

  1. 70 ft
  2. 58 cm
  3. 28 cm
  4. 104 ft
  5. 130 ft
  6. 56 ft
  7. 24 in
  8. 20 cm
  9. 28.3 in
  10. 18.8 cm
  11. 44.0 ft
  12. 53 m

Module 9: Percents Part 1

  1. 47\%
  2. 53\%
  3. \frac{71}{100}
  4. \frac{1.3}{100}=\frac{13}{1000}
  5. \frac{0.04}{100}=\frac{1}{2500}
  6. \frac{106}{100}=\frac{53}{50}
  7. 0.71
  8. 0.013
  9. 0.0004
  10. 1.06
  11. 23\%
  12. 7\%
  13. 8.5\%
  14. 250\%
  15. 28\%
  16. 12.5\%
  17. 31.5
  18. 22.5
  19. 67.5
  20. 100
  21. 38.6
  22. 2.25
  23. \textdollar9.35
  24. \textdollar119.32

Module 10: Ratios, Rates, Proportions

  1. \frac{3}{8}
  2. \frac{105\text{ mi}}{2\text{ hr}}
  3. \frac{52.5\text{ mi}}{1\text{ hr}} or 52.5 miles per hour
  4. \approx\textdollar0.335/oz, or 33.5¢/oz
    Carmella Creeper parties like it’s 1995.
  5. \approx\textdollar0.281/oz, or 28.1¢/oz
  6. \approx\textdollar0.281/oz, or 28.1¢/oz
  7. \frac{3}{4}=\frac{3}{4}; true
  8. \frac{2}{3} \neq \frac{4}{5}; false
  9. 168 = 168; true
  10. 200 \neq 240; false
  11. 70 \neq 60; false
  12. 20 = 20; true
  13. x = 12
  14. n = 5
  15. k = 4
  16. w = 10
  17. x = 10.4
  18. m = 2.0
  19. 256 miles
  20. 20 hours
  21. \approx 50 miles (rounding to one sig fig seems like a good idea here)
  22. 190 pixels wide

Module 11: Scientific Notation

  1. Earth’s mass is larger because it’s a 25-digit number and Mars’ mass is a 24-digit number, but it might take a lot of work counting the zeros to be sure.
  2. Earth’s mass is about ten times larger, because the power of 10 is 1 higher than that of Mars.
  3. A chlorine atom’s radius is larger because it has 9 zeros before the significant digits begin, but a hydrogen atom’s radius has 10 zeros before the significant digits begin. As above, counting the zeros is a pain in the neck.
  4. The chlorine atom has a larger radius because its power of 10 is 1 higher than that of the hydrogen atom. (Remember that -10 is larger than -11 because -10 is farther to the right on a number line.)
  5. \textdollar100,000; 1.00000\times10^5
  6. \textdollar999,999; 9.99999\times10^5
  7. 1.234 \times 10^3
  8. 1.02 \times 10^7
  9. 8.70 \times 10^{-4}
  10. 7.32 \times 10^{-2}
  11. 35,000
  12. 90,120,000
  13. 0.00825
  14. 0.000014
  15. 8 \times 10^7
  16. 3.5 \times 10^{13}
  17. 6 \times 10^{-5}
  18. 4.8 \times 10^5
  19. 1,260 people per square mile
  20. 250 people per square mile
  21. the proton’s mass is roughly 1,830 or 1.83 \times 10^3 times larger
  22. 335.9 \times 10^6; 3.359 \times 10^8
  23. 8.020 \times 10^9; 8.020 \times 10^9
  24. 33.9 \times 10^{12}; 3.39 \times 10^{13}
  25. \approx\textdollar101,000 per person

Module 12: Percents Part 2 and Error Analysis

  1. 93\% or 93.3\%
  2. 37.5\%
  3. \textdollar2,500
  4. 720
  5. 93\% or 93.3\%
  6. 37.5\%
  7. \textdollar2,500
  8. 720
  9. 44.8\% or 45\%
  10. 50 grams of added sugars is the recommended daily intake for a 2,000 calorie diet.
  11. 56\% increase
  12. 10.1\% sales tax
  13. 36\% decrease
  14. 2.7\% decrease
  15. 0.1875\div25\approx0.75\%
  16. 0.13\div10.8\approx1.2\%
  17. 4.806 g; 5.194 g
  18. 3.88\%
  19. 5.443 g; 5.897 g
  20. 4.00\%

Module 13: The US Measurement System

We generally won’t worry about significant figures in these answers; we’ll probably say “2 miles” even if “2.000 miles” is technically correct.

  1. 54 in
  2. 54 ft
  3. 36 in
  4. 1,760 yd
  5. 14\frac{2}{3} ft or 14 ft 8 in
  6. 15 yd
  7. 2 mi
  8. 30 yd
  9. 40 oz
  10. 2,400 lb
  11. 18.75 lb
  12. 32,000 oz
  13. 48 fl oz
  14. 7 pt
  15. 8 pt
  16. 5 c
  17. 1.25 gal
  18. 64 fl oz
  19. 3 lb 7 oz
  20. 7 c 3 fl oz
  21. 15 ft 2 in
  22. 4 t 500 lb
  23. 20 lb or 20 lb 0 oz combined
  24. 3 lb 2 oz heavier
  25. 9 ft 1 in combined
  26. 1 ft 5 in longer

Module 14: The Metric System

  1. 5 m
  2. 28 cm
  3. 3.8 km
  4. 1.6 m
  5. 160 cm
  6. 3 mm
  7. 536 cm
  8. 5,360 mm
  9. 1,609 m
  10. 160,900 cm
  11. 0.297 m
  12. 29.7 cm
  13. 0.828 km
  14. 82.8 dam
  15. 100 g
  16. 80 kg
  17. 500 mg
  18. 2,000 kg
  19. 2,270 g
  20. 2,270,000 mg
  21. 6,500 cg
  22. 65,000 mg
  23. 0.065 kg
  24. 9.5 cg
  25. 0.095 g
  26. 50 L
  27. 30 mL
  28. 0.5 L
  29. 10.5 dL
  30. 1,750 mL
  31. 0.25 L
  32. they are equal in size
  33. about 11 to 1
  34. 4 bottles; this is easier if you know that a 500-milliliter bottle of Mexican Coke is called a medio litro.
    Doce litros de Coca-Cola

Module 15: Converting Between Systems

We may round some of these answers to three significant figures even if the given number has fewer than three sig figs. On the other hand, you’ll see that some of these answers include a critique of a manufacturer’s decision to round numbers a certain way.

  1. 31\text{ mi}
  2. 183\text{ cm}
  3. 164.0\text{ ft}
  4. yes, 4\text{ in}=101.6\text{ mm} according to the conversion, but is it really 4.000\text{ in} to begin with? Rounding the result to 100\text{ mm} or 102\text{ mm} seems reasonable.
  5. 20 in converts to around 50.8 cm, and 50.0 cm converts to around 19.7 in. It looks like somebody used the conversion 1\text{ in}=2.5\text{ cm}, which is fine if you’re estimating but not if you’re going to report a number to three sig figs.
  6. not exactly but they’re pretty close; the error is around 0.3\%.
  7. yes; using either conversion gives a result of 294.8 kg, rounded to the nearest tenth. However, it doesn’t make sense for this to be accurate to four sig figs. It would be best to round to 295 or perhaps even 3\overline{0}0 kg.
  8. not exactly; using 1 kg \approx 2.205 lb gives a result of 1,473.9 kg, and using 1 lb \approx 0.4536 kg gives a result of 1,474.2 kg. Again, the accuracy here doesn’t make sense, especially when you consider that the numbers on the box don’t agree with each other: 294.8\cdot5\neq1,474.1.
  9. 11\text{ lb}
  10. \approx230\text{ g}
  11. \approx110\text{ g}
  12. \approx1.8\text{ oz}
  13. about \textdollar1.09
  14. about \textdollar0.99
  15. \approx1.3\text{ gal}
  16. 355\text{ mL}
  17. 3.4\text{ fl oz}
  18. no matter which conversion you use, the result should round to 22.7 liters.
  19. a bit less than 600\text{ km}
  20. 11\text{ km/L}

Module 16: Other Conversions

We will generally round these answers to three significant figures; your answer may be slightly different depending on which conversion ratio you used.

  1. 525,600 min; if you’re familiar with the musical Rent, then you already knew the answer.
  2. this is roughly 31.7 years, which is indeed possible
  3. 37.6 km/hr
  4. 23.3 mi/hr
  5. 1,770 mi/hr
  6. 29.5 mi in 1 min
  7. 20.3 min
  8. 0.17 mi/gal
  9. 5.8 gal/mi
  10. 171 gal in 1 min
  11. the capacity increased by a factor of 14.4
  12. 4 times greater
  13. 1,200 megawatts per home
  14. 1 watt per gallon
  15. 2,500 times more powerful
  16. 0.4 ms, 0.04 ms, 0.004 ms; 400 μs, 40 μs, 4 μs
  17. the ratio of the wavelengths of red and infrared is 7 to 100;
    the ratio of the wavelengths of infrared and red is around 14 to 1
  18. this is equivalent to 2,500 chest x-rays

Module 17: Angles

  1. right angle
  2. obtuse angle
  3. reflexive angle
  4. straight angle
  5. acute angle
  6. a=127^\circ; b=53^\circ; c=127^\circ
  7. 27^\circ
  8. 97^\circ
  9. 23^\circ each
  10. 45^\circ each
  11. 60^\circ each
  12. A=61^\circ; B=80^\circ; C=39^\circ
  13. 18.9111^\circ
  14. 155.6808^\circ
  15. 34.1924^\circ
  16. 29^\circ58'30''
  17. 31^\circ8'15''
  18. 76^\circ20'48.1''

Module 18: Triangles

  1. right isosceles triangle
  2. obtuse scalene triangle
  3. acute equilateral triangle (yes, an equilateral triangle will always be acute)
  4. w=35\text{ ft}
  5. x=8\text{ cm}y=10.5\text{ cm}
  6. d=268\text{ ft}
  7. n=55\text{ cm}
  8. this is a right triangle, because 5^2+12^2=13^2.
  9. this is not a right triangle, because 8^2+17^2\neq19^2.
  10. 7.07
  11. 17.20
  12. 30.71
  13. 10\text{ ft}
  14. 15\text{ ft}
  15. 12.3\text{ cm}
  16. 1.8\text{ cm}

Module 19: Area of Polygons and Circles

We may occasionally include extra sig figs in these answers so you can be sure that your answer matches ours.

  1. 20\text{ cm}^2
  2. 16\text{ cm}^2
  3. 4.86\text{ m}^2
  4. 12.25\text{ ft}^2
  5. 120\text{ in}^2
  6. 360\text{ m}^2
  7. 210\text{ ft}^2
  8. 126\text{ cm}^2
  9. 38.5\text{ cm}^2
  10. 204\text{ ft}^2
  11. 2,160\text{ in}^2
  12. 36\text{ m}^2
  13. 124\text{ cm}^2
  14. 192\text{ cm}^2
  15. 28.3\text{ cm}^2
  16. 220\text{ m}^2
  17. 154\text{ ft}^2
  18. 63.6\text{ in}^2

Module 20: Composite Figures

  1. 64\text{ ft}
  2. 189\text{ ft}^2
  3. 590\text{ cm}^2; the area of the rectangle is 800\text{ cm}^2 and the areas of the triangles are 70\text{ cm}^2 and 140\text{ cm}^2.
  4. 590\text{ cm}^2; hey, that’s what we got for #3!
  5. 148\text{ m}
  6. 940\text{ m}^2
  7. Based on the stated measurements, the distance around the track will be 401 meters, which appears to be 1 meter too long. In real life, precision would be very important here, and you might ask for the measurements to be given to the nearest tenth of a meter.
  8. around 9,620\text{ m}^2
  9. 1,960\text{ cm}^2
  10. 178.5\text{ cm}
  11. 29\text{ ft}^2
  12. 47\text{ ft}
  13. around 21.5\% (Hint: Make up an easy number for the side of the square, like 2 or 10.)
  14. around 36.3\% (Hint: The diagonals of the square are equal to the circle’s diameter.)

Module 21: Converting Units of Area

We may occasionally include extra sig figs in these answers so that you can be sure that your answer matches ours.

  1. 162\text{ ft}^2
  2. 162\text{ ft}^2
  3. 7\text{ ft}^2
  4. 7\text{ ft}^2
  5. 7,776\text{ in}^2
  6. 8.3\text{ ac}
  7. 180,000\text{ cm}^2
  8. 180,000\text{ cm}^2
  9. 623.7\text{ cm}^2
  10. 623.7\text{ cm}^2
  11. 6\text{ m}^2
  12. 4\text{ ha}
  13. 376\text{ km}^2
  14. 2,\overline{0}00\text{ ha}, rounded to two sig figs
  15. 603\text{ cm}^2
  16. 75,300\text{ ft}^2, rounded to three sig figs
  17. 154\text{ in}^2
  18. 38.5\text{ in}^2
  19. 4 to 1; if we double the linear measurement, we get four times the area.
  20. 54\text{ cm}^2
  21. 6\text{ cm}^2
  22. 9 to 1; if we triple the linear measurement, we get nine times the area.

Module 22: Surface Area of Common Solids

  1. 36\text{ cm}^2
  2. 76\text{ cm}^2
  3. 471\text{ cm}^2
  4. 628\text{ cm}^2
  5. 616\text{ cm}^2
  6. 380\text{ in}^2

Module 23: Area of Regular Polygons

All answers have been given to two or three significant figures.

  1. 6,900\text{ in}^2
  2. 94\text{ cm}^2
  3. 750\text{ in}^2
  4. 751\text{ mm}^2
  5. 480\text{ cm}^2
  6. 110\text{ m}^2
  7. 280\text{ mm}^2 (the area of the circle \approx1,660\text{ mm}^2 and the area of the hexagon is 1,380\text{ mm}^2)

Module 24: Volume of Common Solids

  1. 40\text{ cm}^3
  2. 531\text{ cm}^3
  3. 45\text{ cm}^3
  4. 350\text{ cm}^3
  5. 520\text{ cm}^3
  6. 22,600\text{ ft}^3
  7. 3.7\text{ mm}^3
  8. 1,440\text{ cm}^3
  9. 697\text{ in}^3 or 7\overline{0}0\text{ in}^3
  10. 22.7\text{ cm}^3 (the cylinder’s volume \approx14.1\text{ cm}^3 and the hemisphere’s volume \approx8.6\text{ cm}^3.)
  11. 37.6\text{ ft}^3 (the cylinder’s volume \approx29.45\text{ ft}^3 and the two hemispheres’ combined volume \approx8.18\text{ ft}^3)
  12. 37.6\text{ ft}^3\approx282\text{ gal}, which is more than 250\text{ gal}.

Module 25: Converting Units of Volume

  1. the result is very close to 1 cubic yard: (112\text{ in}\cdot14\text{ in}\cdot10\text{ in})\cdot3\text{ crates}=47,040\text{ in}^3\approx1.01\text{ yd}^3
  2. this estimate is also 1 cubic yard: (9\text{ ft}\cdot1\text{ ft}\cdot1\text{ ft})\cdot3\text{ crates}=27\text{ ft}^3=1\text{ yd}^3
  3. around 60 gallons
  4. yes, the can is able to hold 12 fluid ounces; the can’s volume is roughly 23.3\text{ in}^3\approx12.9\text{ fl oz}.
  5. 5 gallons
  6. around 2,300 to 2,400 liters; a calculator says 2,356 liters which should technically be rounded up to 2,400 liters, but it would be reasonable to round down to 2,300 liters instead if you considered the volume of the benches and the fact that the sides might slope inwards near to bottom of the tub.
  7. the rectangular section of the carton has a volume of 1.7 liters, which is larger than the required 1.5\text{ L}.
  8. \approx21\text{ cm} high
    Independent verification from my kitchen.
  9. 19.6\text{ yd}^3
  10. 53\overline{0}\text{ ft}^3
  11. 1.53\text{ m}^3
  12. 327\text{ in}^3
  13. 5,350\text{ cm}^3
  14. 5.35\text{ L}
  15. 0.5\text{ ft}^3\approx14.16\text{ L}; assuming that it’s 0.50\text{ ft}^3, these measures are equivalent to two sig figs.
  16. 100\text{ lb/ft}^3
  17. 31\text{ lb}; now you can laugh whenever you see someone in a heist movie load a cheap duffel bag with gold bars and carry it out of the vault.
  18. 1.1\text{ kg}
  19. 268\text{ cm}^3
  20. 33.5\text{ cm}^3
  21. 8 to 1
  22. 1,620\text{ in}^3
  23. 60\text{ in}^3
  24. 27 to 1

Module 26: Pyramids and Cones

  1. 1,280\text{ cm}^3
  2. 2,420,000\text{ m}^3
  3. 544\text{ cm}^2; 80\overline{0}\text{ cm}^2
  4. 82,300\text{ m}^2
  5. 310\text{ cm}^3 (if we had greater accuracy, the result would be 314.16 because it’s 100 times \pi.)
  6. 38\text{ ft}^3
  7. 47\text{ ft}^2; 75\text{ ft}^2
  8. 2\overline{0}0\text{ cm}^2; 280\text{ cm}^2

Module 27: Percents Part 3

  1. \textdollar1,299.00
  2. 14,861 students; notice that if the percent had fewer than five sig figs, we wouldn’t have been able to get an answer that was accurate to the nearest whole number.
  3. Yes, you can! Each bottle cost \textdollar3.59.
    Real time screenshot of my phone’s calculator.
  4. \textdollar3.20 million
  5. 873,900 people
  6. \textdollar16; the percent has only two sig figs, so it doesn’t make sense to assume that the price was \textdollar16.13. They probably rounded the percent from 68.75\% to make the numbers in the advertisement seems less complicated.

Module 28: Mean, Median, Mode

  1. 10.3\text{ min}
  2. \textdollar4.488
  3. 11.0\text{ min} (because it is the seventh value in the list of thirteen)
  4. \textdollar4.475
  5. \textdollar256,000
  6. \textdollar250,000
  7. \textdollar338,000
  8. \textdollar275,000
  9. the median is more representative because the mean is higher than five of the six home values.
  10. 11.0\text{ min} (because it appears four times in the list)
  11. no mode (there are no repeated values)
  12. AT&T Mobility
  13. Samoas and Thin Mints
  14. 12.2 games
  15. 12 games
  16. 12 games
  17. they all represent the data fairly well; 12 wins represents a typical Patriots season.
  18. 6.8 games
  19. 7 games
  20. 6 games
  21. they all represent the data fairly well; 6 or 7 wins represents a typical Bills season.
  22. 98.2 grams; the mean doesn’t seem to represent a typical clementine because there is a group of smaller ones (from 82 to 94 grams) and a group of larger ones (from 102 to 109 grams) with none in the middle.
  23. 94 grams; for the same reason, the median doesn’t represent a typical clementine, but you could say it helps split the clementines into a lighter group and a heavier group.
  24. no mode; too many values appear twice.
  25. 98.3 grams; this is a small increase over the previous mean.
  26. 94 grams; the median does not change when one of the highest numbers increases.
  27. 109 grams; you might say it represents the mass of a typical large clementine, but it doesn’t represent the entire group.

Module 29: Probability

  1. \frac{6}{36}=\frac{1}{6}
  2. \frac{2}{36}=\frac{1}{18}
  3. \frac{8}{36}=\frac{2}{9}
  4. \frac{36}{36}=1
  5. \frac{0}{36}=0
  6. \frac{4}{36}=\frac{1}{9}
  7. \frac{32}{36}=\frac{8}{9}
  8. \frac{6}{36}=\frac{1}{6}
  9. \frac{30}{36}=\frac{5}{6}
  10. \frac{15}{60}=\frac{1}{4}=0.25=25\%
  11. \frac{45}{60}=\frac{3}{4}=0.75=75\%
  12. \frac{18}{60}=\frac{3}{10}=0.3=30\%
  13. \frac{42}{60}=\frac{7}{10}=0.7=70\%
  14. \frac{1}{4}=25\%
  15. \frac{3}{4}=75\%
  16. \frac{2}{4}=50\%
  17. \frac{2}{4}=50\%
  18. \frac{8}{250}=3.2\%
  19. \frac{242}{250}=96.8\%
  20. we should expect 968 copies to be acceptable
  21. \frac{44}{200}=22\%
  22. we should expect 220 tax returns to have errors
  23. 22\%=0.22
  24. (0.22)^2\approx4.8\%
  25. (0.22)^3\approx1.1\%
  26. 0.22\cdot0.78\approx17.2\%
  27. 0.78\cdot0.22\approx17.2\%
  28. (0.78)^2\approx60.8\%
  29. (0.78)^3\approx47.5\%
  30. 1-(0.78)^3\approx52.5\%

Module 30: Standard Deviation

  1. 60.5; 66.5
  2. 57.5; 69.5
  3. 54.5; 72.5
  4. 66.5; 72.5
  5. 63.5; 75.5
  6. 60.5; 78.5
  7. 68\% because 100\%-(16\%+16\%)=68\%
  8. 195 lb because this is halfway between 160 and 230 lb
  9. 35 lb because 195-35 lb and 195+35 lb encompasses 68\% of the data
  10. 125; 265
  11. 8.8; 15.6
  12. You would not have predicted this from the data because it is more than two standard deviations below the mean, so there would be a roughly 2.5\% chance of this happening randomly. In fact, (12.2-7)\div1.7 is slightly larger than 3, so this is more than three standard deviations below the mean, making it even more unlikely. (You might have predicted that the Patriots would get worse when Tom Brady left them for Tampa Bay, but you wouldn’t have predicted only 7 wins based on the previous nineteen years of data.)
  13. 3.4; 10.2
  14. You would not predict this from the data because it is more than two standard deviations above the mean, so there would be a roughly 2.5\% chance of this happening randomly. In fact, (13-6.8)\div1.7\approx3.6, so this is more than three standard deviations above the mean, making it even more unlikely. This increased win total is partly due to external forces (i.e., the Patriots becoming weaker and losing two games to the Bills) but even 11 wins would have been a bold prediction, let alone 13.
  15. 3.9; 14.3
  16. The trouble with making predictions about the Broncos is that their standard deviation is so large. You could choose any number between 4 and 14 wins and be within the 95\% interval. (9.1-5)\div2.6\approx1.6, so this is around 1.6 standard deviations below the mean, which makes it not very unusual. Whereas the Patriots and Bills are more consistent, the Broncos’ win totals fluctuate quite a bit and are therefore more unpredictable.

Module 31: Right Triangle Trigonometry

  1. the adjacent side is e, the opposite side is f, and the hypotenuse is d.
  2. the adjacent side is x, the opposite side is y, and the hypotenuse is r.
  3. \frac{3}{5}=0.6
  4. \frac{4}{5}=0.8
  5. \frac{3}{4}=0.75
  6. \frac{4}{5}=0.8
  7. \frac{3}{5}=0.6
  8. \frac{4}{3}\approx1.333
  9. 0.6000
  10. 0.8000
  11. 0.7500
  12. 0.8000
  13. 0.6000
  14. 1.333
  15. z\approx4.6\text{ cm}
  16. g\approx2.6\text{ cm}
  17. b\approx5.706\text{ in}
  18. p\approx75.51\text{ mm}
  19. y\approx136.18\text{ mm}
  20. d\approx296.87\text{ mm}
  21. the wire is approximately 27\text{ ft} long
  22. \approx17.85\text{ ft}, which is roughly 17\text{ ft}, 10\text{ in}
  23. No; 64\cdot\text{tan }1^\circ\approx1.1\text{ ft}, so the puck will hit the fabric over 1 foot away from the center of the hole. (The person in the photo was given a bunch of pucks and 30 seconds to score, but he scored on his first shot. Boston Bruins at Vancouver Canucks, February 24, 2024.)
  24. 36.87^\circ
  25. 60^\circ
  26. 53.13^\circ
  27. \angle A\approx36.47^\circ
  28. \angle1\approx42.03^\circ
  29. \angle1\approx30.76^\circ
  30. \angle y\approx52.88^\circ
  31. \angle1\approx55.28^\circ
  32. \angle x\approx31.50^\circ; \angle y\approx58.50^\circ
  33. \text{tan}^{-1}\left(\frac{4}{1}\right)\approx76^\circ angle of elevation
  34. Yes; \text{sin}^{-1}\left(\frac{2}{25}\right)\approx4.59^\circ, which is less than 4.75^\circ.
  35. \text{tan}^{-1}\left(\frac{17}{14}\right)\approx50.5^\circ
  36. 17\div\text{sin }51^\circ\approx22.0
  37. 14\div\text{cos }51^\circ\approx22.0
  38. \sqrt{14^2+17^2}\approx22.0
  39. All three answers are the same rounded to three significant figures. This is true because we rounded \angle A to the nearest tenth; if we had rounded it to 51^\circ instead of 50.5^\circ, we would have decreased the accuracy of #36 & #37 to only two sig figs and the three results all would have been slightly different.
  40. \approx23^\circ
  41. \approx8,900\text{ ft}

Module 32: Slope

  1. 0.36\text:12, 0.03, 3\%
  2. 0.60\text:12, 0.05, 5\%
  3. 1.00\text:12, 0.0833, 8.33\%
  4. 2.16\text:12, 0.18, 18\%
  5. 1.72^\circ
  6. 2.86^\circ
  7. 4.76^\circ
  8. 10.20^\circ
  9. 0.5\text{ ft}
  10. 1\text{ ft}
  11. 5\text{ ft}
  12. \text{tan}^{-1}\left(20/12\right)\approx59^\circ from vertical. (this would be an angle of depression of 31^\circ.)
  13. 30\text{ ft}; the proportion \frac{1}{12}=\frac{2.5}{x} gives a result of exactly 30\text{ ft}.
    Using the result from #7, the equation \text{tan}\left(4.76^\circ\right)=\frac{2.5}{x} gives a result very close to 30.0\text{ ft}.

Module 33: Non-Right Triangle Trigonometry

  1. k\approx61\text{ in}
  2. a=c=74^\circx\approx5.168\text{ in}
  3. x\approx11.6\text{ cm}; y\approx12.3\text{ cm}
  4. the shorter wire is roughly 23.5 feet; the longer wire is roughly 26 feet.
    a photograph of the actual utility pole that is described in exercise 4
    Exercise 4 is based on actual events!
  5. n\approx72.4^\circ
  6. n\approx107.6^\circ
  7. d\approx65\text{ mm}
  8. p\approx11.4\text{ cm}
  9. w\approx14.12\text{ m}
  10. the distance across the pond is roughly 81.5 meters.
  11. X\approx19.4^\circ; Y\approx133.5^\circ; Z\approx27.1^\circ

Module 34: Radian Measure

  1. \frac{\pi}{6}
  2. \frac{\pi}{4}
  3. \frac{\pi}{3}
  4. \frac{\pi}{2}
  5. \frac{2\pi}{3}
  6. \frac{5\pi}{4}
  7. \frac{4\pi}{3}
  8. \frac{3\pi}{2}
  9. 15^\circ
  10. 135^\circ
  11. 150^\circ
  12. 315^\circ
  13. \approx57.3^\circ

 

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Technical Mathematics, 2nd Edition Copyright © 2024 by Morgan Chase is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.