Exercise Answers: Module 32

Slope

$0.36\text:12$ , $0.03$ , $3\%$
$0.60\text:12$ , $0.05$ , $5\%$
$1.00\text:12$ , $0.0833$ , $8.33\%$
$2.16\text:12$ , $0.18$ , $18\%$
$1.72^\circ$
$2.86^\circ$
$4.76^\circ$
$10.20^\circ$
$0.5\text{ ft}$
$1\text{ ft}$
$5\text{ ft}$
$\text{tan}^{-1}\left(20/12\right)\approx59^\circ$ from vertical. (this would be an angle of depression of $31^\circ$ .)
$30\text{ ft}$ ; the proportion $\frac{1}{12}=\frac{2.5}{x}$ gives a result of exactly $30\text{ ft}$ . Using the result from Exercise 7, the equation $\text{tan}\left(4.76^\circ\right)=\frac{2.5}{x}$ gives a result very close to $30.0\text{ ft}$ .

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