We now know to find average acceleration of an object by finding the net force and applying Newton’s Second Law. Once the acceleration is known, we can figure out how the velocity and position change over time. That process is known as kinematics and the equations we use to relate acceleration, velocity, position, and time are known as the kinematic equations. Let’s take a look at a few of them one-by-one.
Based on our definition of as the rate of change of the we can calculate the change in velocity during a time interval as the acceleration multiplied by the length of the time interval:
If a person has an acceleration of 5.0 m/s/s, how much does their velocity change in 3.0 s?
We can find the current velocity by adding the expression for change in velocity to the :
If the person in the previous exercise has an initial velocity of 2.0 m/s, what is their new velocity after the 3.0 s?
We can calculate the during the interval as the average of the initial and final velocities:
What is the average velocity of the person in the previous exercise?
Using the definition of velocity as the rate of change of we can calculate the change in position during a time interval as the during the interval multiplied by the length of the time interval.
What is the change in position of the person in the previous exercises?
Adding the above expression for change in position to the allows us to calculate the after any time:
If the person in the previous exercises started at a position of 4 m/s, what is their final position?
We can combine everything the from previous steps into a single equation that can save some time on some problems. It looks like this:
To get the above equation we used equation (3) to replace the average velocity with the expression for average velocity:
Using equation (2) we can then replace the final velocity:
After some simplification we are there:
A car accelerates from rest at 3 m/s/s. What is the car’s velocity after 5 s and how far does the car move in the first 5 s ? [Hint: The car starts from rest so the is zero.]
After leaving a friend’s 3rd story apartment you get to your car and realize that you have left your keys in the apartment. You call your friend and ask them to drop the keys out the window to you. We want to figure out how long it will take the keys to reach you and how fast they will be falling when they get there. The third story window is about 35 ft off the ground. We can convert to meters and use our previously stated acceleration for falling objects, g =9.8 m/s/s, or we can stick with feet and use g = 32 ft/s/s, so let’s do that.
Starting from our last equation from the work we did above:
We choose upward as our positive direction and the ground as our , therefore our is 35 ft and our is 0 ft. The keys are dropped from rest, so our is zero. Putting the zeros into the equation above we have:
Now we can isolate the time variable:
Take the square root to find the time
Entering our known values we can find the fall time. We will use -32 ft/s/s for our because the acceleration due to gravity is downward and we have chosen upward as the positive direction.
Lastly, we can find the of the keys using equation (2) above
The final velocity of 47 ft/s is about 32 MPH. If the keys smack your hand at that speed, it will hurt. There are techniques you could use to prevent injury in such a situation, and those techniques will be the topic of the next Unit.
In solving the previous example we found an equation to calculate the time required for an object with a certain acceleration to reach a final position of zero when starting from a known initial position. Among other things, this allows us to calculate the time required to fall to the ground from a certain starting height. That equation will come up often, so lets write it out here:
If acceleration is set to -9.8 m/s/s (or -g), then this equation calculates the free-fall time for a choice of negative as the downward direction.
Calculate the time required for a person to fall from a height of 0.75 m. From this height, the person will not move fast enough for drag force to become important, so you may assume they are in free-fall.
We have learned in the last few chapters that our example skydiver has an initial of 9.8 m/s/s and an acceleration of zero after reaching terminal velocity, so between those points the acceleration must be changing. The rate of change of the acceleration is known as the jerk, but we won’t deal with jerk in this textbook and will instead focus on motion with acceleration. However, if we really want to analyze our skydiver’s full motion, we will need to somehow deal with a changing acceleration. That’s what the next chapter is all about.
the change in velocity per unit time, the slope of a velocity vs. time graph
a quantity of speed with a defined direction, the change in speed per unit time, the slope of the position vs. time graph
the value of velocity at the start of the time interval over which motion is being analyzed
the average of all instantaneous velocities that occurred within a certain time interval, equal to the displacement divided by the time interval
location in space defined relative to a chosen origin, or location where the value of position is zero
position at the start of the time interval over which motion is being analyzed
position at the end of the time interval over which motion is being analyzed
location where the position is zero
not changing, having the same value within a specified interval of time, space, or other physical variable